On receiving server B:
madhu@192.168.1.100:~$ while true; do netcat -vvlnp 5656 > /dev/null; done
Listening on [0.0.0.0] (family 0, port 5656)
Connection from [192.168.1.100] port 5656 [tcp/*] accepted (family 2, sport 53714)
Listening on [0.0.0.0] (family 0, port 5656)
On sending server A:
dd if=/dev/zero bs=1024k count=1024 | nc -vvn 192.168.1.100 5656
Based on the results, it’s evident that we successfully transmitted 1 GB of data at a rate of 82.1 MB/s (Megabytes per second).
However, considering that network speed is typically measured in bits, we need to convert MB (Megabytes) to Mb (Megabits) using the formula:
82.1 * 8 = 656 Mbps (Megabits per second) (This calculation involves multiplying by 8, as 1 byte equals 8 bits.)
Therefore, our data transfer from server A to server B amounted to 1 GB at a speed of 656 Mbps (Megabits per second).
